Answer by Criminal_Affair_At_SO for handling void type in template
Late to the party, especially since C++17 if constexpr solves this perfectly, but if you are limited to C++11, here is my solution:For the variable, use a type helper:template <typename T> struct...
View Articlehandling void type in template
I have a templated function that invokes another function and stores its return value, then does some work before returning the value. I'd like to extend this to handle T = void, and was wondering if...
View ArticleAnswer by gustaf r for handling void type in template
No, you need the specialization since you cannot store void (as in T result = Func();).If you're never gonna use the value, and you are fine with calling Func as the last thing, then you can...
View ArticleAnswer by Pubby for handling void type in template
If all you're doing is taking and releasing a lock then you should use RAII instead of calling lock/unlock functions. This is especially true if Func could throw, as if it does the code after it will...
View ArticleAnswer by K-ballo for handling void type in template
Given that your operation does not depend on the result of the function, you can do it without a specialization. It is ok for a function returning void to return an expression of type void. So the...
View ArticleAnswer by Eric for handling void type in template
Not certain this is valid, but:template<>void Foo<T>( T(*Func)() ) { // do something first (e.g. some setup) return tearDown(Func());}template<>T tearDown<T>( T result) { // do...
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